25x-20x=20x^2

Solution for 25x-20x=20x^2 equation:

25x-20x=20x^2

We move all terms to the left:

25x-20x-(20x^2)=0

determiningTheFunctionDomain
-20x^2+25x-20x=0

We add all the numbers together, and all the variables

-20x^2+5x=0

a = -20; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-20)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-20}=\frac{-10}{-40}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-20}=\frac{0}{-40}
=0
$